36p^2-65p-1=0

Solution for 36p^2-65p-1=0 equation:

36p^2-65p-1=0

a = 36; b = -65; c = -1;
Δ = b2-4ac
Δ = -652-4·36·(-1)
Δ = 4369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-\sqrt{4369}}{2*36}=\frac{65-\sqrt{4369}}{72}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+\sqrt{4369}}{2*36}=\frac{65+\sqrt{4369}}{72}
$